Quick answer

Enter logarithm value y and base b. The tool returns antilog = b^y in your browser.

Formula

  • Input: y (log value)
  • Input: b (base)
  • Output: b^y with formula strip

Introduction

The calculator on the home page is designed for the inverse-log workflow students use most often: given y and b, return the original-scale number.

It stays in the hero section so you can compute before reading longer theory sections on the same page.

Open the Antilog Calculator at the top whenever you want to pair button presses with the written method below.

What the calculator does

It evaluates exponentiation b^y, which is the mathematical definition of an antilog. There is no second hidden formula behind the scenes.

Validation blocks invalid bases (zero, negative, or 1) and shows short error text so you know whether the logarithm value or the base needs fixing.

Scientific notation such as 2.5e-4 is accepted when problems use engineering notation, which is common in physics and chemistry labs.

If you want the pencil-and-paper order of operations spelled out before you rely on buttons, read how to calculate an antilog and keep that checklist beside the keyboard.

Fields on screen

Logarithm value → y
with base → b
Result: Antilog → b^y

The formula strip shows substitution so you can copy notation directly into homework. Seeing b^y update live helps connect calculator output to the power form teachers mark on papers.

After a few sessions, test yourself against the numeric cases in antilog examples to make sure you can predict results before you type them.

Using the tool

  1. Enter the log value. Type the exponent y from log_b(x) = y. Fractions and negative exponents are allowed when the problem uses them.
  2. Enter the base. Default is 10 for common antilog drills. Type e or 2.71828 for natural antilog problems.
  3. Read the antilog panel. Check the large result and the formula line together so you learn both the number and the notation.
  4. Reset between problems. Reset clears fields and returns the base to 10, which is useful in a classroom setting when problems switch from common to natural logs.

Sample sessions

Session A: log value 3, base 10, output 1000 because 10^3 = 1000.

Session B: log value 2, base e, output about 7.389 because e^2 ≈ 7.389.

Session C: log value -1, base 10, output 0.1 because 10^(-1) = 1/10.